
以傾角變位法計算
C點位移`Delta`(向下)
側位移之比`Delta_(AB):Delta_(CB)=3:5
`M_(AB)=1.35X10^6Delta
`M_(CB)=-10^6Delta
鋼索內力S=`46.875X10^3Delta`
由力平衡

`sumM_O=0 =>M_(AB)-M_(AB)/(200)X(200+180)+M_(CB)-SX180+15000X240=0`
`=>Delta=(1440)/(4261)=0.338`"(向下)
`Delta_(Bh)=0.75Delta=0.253`"(向左)
代回得
`M_(AB)=456.23`K-in=`38.02K-ft(順時針)
`M_(CB)=-28.16K-ft(逆時針)`
ANS:
(a)鋼索內力S=15.844K(拉力)
(b)B點水平位移`Delta_(Bh)=0.253`"(向左)
以上不知道對不對
請多指教~謝謝~